Lesson 3ª

 

 

 

 

 

   

 

Operations with Algebraic Fractions.

 

10.15 Calculate:

operacionesalgebraicasconfracciones Answer: operacionesalgebraicasconfracciones

Solution:
The l.c.m. of the denominators is the product of both: operacionesalgebraicasconfracciones

Divide it by each denominator. Multiply their quotient by their corresponding numerator. This is an example of the first fraction:

operacionesalgebraicasconfracciones

We have operacionesalgebraicasconfracciones as quotient. We multiply it by the first numerator, which is also operacionesalgebraicasconfracciones. We follow the same process with the second fraction:

operacionesalgebraicasconfracciones

The first numerator is the square of the difference of two numbers and the LCD is equal to a difference of squares:

operacionesalgebraicasconfracciones

We develop the squares of the difference and the sum of the squares of two numbers.

After the negative sign joining the fractions, we write a parenthesis. When we remove them, we change the sign of each term. Then, we reduce any similar terms:

operacionesalgebraicasconfracciones

 

10.16 Calculate:

operacionesalgebraicasconfracciones Answer: operacionesalgebraicasconfracciones

or: operacionesalgebraicasconfracciones

Solution:

The first denominator is the result of multiplying the sum of two numbers by their difference; operacionesalgebraicasconfracciones. Then, the l.c.m. of the denominators will be operacionesalgebraicasconfracciones.

We divide operacionesalgebraicasconfracciones by the second denominator operacionesalgebraicasconfracciones:

operacionesalgebraicasconfracciones

Be careful when you remove a parenthesis with a negative sign in front. We simplify any similar terms:

operacionesalgebraicasconfracciones

operacionesalgebraicasconfracciones

Since a negative sign in front of a fraction only affects the numerator, we could write this result:

operacionesalgebraicasconfracciones

10.17 Calculate:

operacionesalgebraicasconfracciones Answer: operacionesalgebraicasconfracciones

or: operacionesalgebraicasconfracciones

Solution

Step-by-step:

operacionesalgebraicasconfracciones

10.18 Calculate:

operacionesalgebraicasconfracciones Answer: operacionesalgebraicasconfracciones or : operacionesalgebraicasconfracciones

Solution:

The third denominator: operacionesalgebraicasconfracciones is not a product of the other two denominators. The second denominator operacionesalgebraicasconfracciones won't work; it would have to be operacionesalgebraicasconfracciones. The first denominator operacionesalgebraicasconfraccionesworks because we can write it asoperacionesalgebraicasconfracciones.

We have already mentioned that a negative sign in front of a fraction only affects the numerator and this is important in what you are about to see. If we change the sign to both terms in a fraction (numerator and denominator), the result is the same:

Pay attention to the next example:

operacionesalgebraicasconfracciones

If we change the signs to the numerator and denominator, the result will be the same:

operacionesalgebraicasconfracciones

Notice now the same example with the negative sign in front of the fraction:

operacionesalgebraicasconfracciones

As you can see, the result of all cases is the same.

If we haveoperacionesalgebraicasconfracciones, it would be the same as writing: operacionesalgebraicasconfraccionesbecause the negative sign in front of a fraction only affects the numerator.

Imagine that instead of operacionesalgebraicasconfraccioneswe want the denominator to beoperacionesalgebraicasconfracciones: As you can see, we changed the signs of each term in the denominator. If we change the signs of the terms in the denominator, we also have to change the signs in the numerator:

operacionesalgebraicasconfracciones

Since the sign in front of a fraction only affects the numerator, we can write:

operacionesalgebraicasconfracciones

With this in mind, we can solve the exercise:

operacionesalgebraicasconfracciones

We can also solve it by changing the signs of the numerator and denominator in the second fraction: operacionesalgebraicasconfracciones, which is the same as operacionesalgebraicasconfracciones.

operacionesalgebraicasconfracciones

At first look, the results are: operacionesalgebraicasconfracciones.

They seem different but in fact they are the same:

Imagine that x = 2. Substitute x with 2 in the first answer:

operacionesalgebraicasconfracciones

Substitute x with 2 in the second answer:

operacionesalgebraicasconfracciones

We have the same result in both cases.

If we change the signs of each term in the fraction:

operacionesalgebraicasconfraccionesthe result doesn't varyoperacionesalgebraicasconfracciones.

10.19 Calculate:

operacionesalgebraicasconfracciones Answer: operacionesalgebraicasconfracciones.

Solution:

If the denominator of the third fraction were operacionesalgebraicasconfracciones, it would be the l.c.m. of the denominators. This demands a change in the signs of each term in the numerator and denominator in the exercise:

operacionesalgebraicasconfracciones

10.20 Calculate:

operacionesalgebraicasconfracciones

Answer:  Any of the three answers is valid:       

operacionesalgebraicasconfracciones

Solution:
We need to analyse each fraction before calculating. In the denominator of the first fraction, we can take 10 as a common factor. In the denominator of the third fraction, we can take 4 as a common factor. In both cases, we can simplify with a factor of its respective numerator:

operacionesalgebraicasconfracciones

 

From this, we see that the l.c.m. of the denominators is operacionesalgebraicasconfracciones.